4(3m+4)-2(2m+3)=15

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Solution for 4(3m+4)-2(2m+3)=15 equation: 



4(3m+4)-2(2m+3)=15

We move all terms to the left:

4(3m+4)-2(2m+3)-(15)=0

We multiply parentheses

12m-4m+16-6-15=0

We add all the numbers together, and all the variables

8m-5=0

We move all terms containing m to the left, all other terms to the right

8m=5

m=5/8

m=5/8

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