4(3m+5)=2(9-m)

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Solution for 4(3m+5)=2(9-m) equation: 



4(3m+5)=2(9-m)

We move all terms to the left:

4(3m+5)-(2(9-m))=0

We add all the numbers together, and all the variables

4(3m+5)-(2(-1m+9))=0

We multiply parentheses

12m-(2(-1m+9))+20=0



We calculate terms in parentheses: -(2(-1m+9)), so:

2(-1m+9)

We multiply parentheses

-2m+18

Back to the equation:

-(-2m+18)



We get rid of parentheses

12m+2m-18+20=0

We add all the numbers together, and all the variables

14m+2=0

We move all terms containing m to the left, all other terms to the right

14m=-2

m=-2/14

m=-1/7

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