4(3m-1)-2(2m+3)=3(m+4)+2m+7

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Solution for 4(3m-1)-2(2m+3)=3(m+4)+2m+7 equation: 



4(3m-1)-2(2m+3)=3(m+4)+2m+7

We move all terms to the left:

4(3m-1)-2(2m+3)-(3(m+4)+2m+7)=0

We multiply parentheses

12m-4m-(3(m+4)+2m+7)-4-6=0



We calculate terms in parentheses: -(3(m+4)+2m+7), so:

3(m+4)+2m+7

We add all the numbers together, and all the variables

2m+3(m+4)+7

We multiply parentheses

2m+3m+12+7

We add all the numbers together, and all the variables

5m+19

Back to the equation:

-(5m+19)



We add all the numbers together, and all the variables

8m-(5m+19)-10=0

We get rid of parentheses

8m-5m-19-10=0

We add all the numbers together, and all the variables

3m-29=0

We move all terms containing m to the left, all other terms to the right

3m=29

m=29/3

m=9+2/3

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