4(3n-1)=(3n+9)+3

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Solution for 4(3n-1)=(3n+9)+3 equation: 



4(3n-1)=(3n+9)+3

We move all terms to the left:

4(3n-1)-((3n+9)+3)=0

We multiply parentheses

12n-((3n+9)+3)-4=0



We calculate terms in parentheses: -((3n+9)+3), so:

(3n+9)+3

We get rid of parentheses

3n+9+3

We add all the numbers together, and all the variables

3n+12

Back to the equation:

-(3n+12)



We get rid of parentheses

12n-3n-12-4=0

We add all the numbers together, and all the variables

9n-16=0

We move all terms containing n to the left, all other terms to the right

9n=16

n=16/9

n=1+7/9

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