4(3n-1)=(3n+9)+3

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Solution for 4(3n-1)=(3n+9)+3 equation:



4(3n-1)=(3n+9)+3
We move all terms to the left:
4(3n-1)-((3n+9)+3)=0
We multiply parentheses
12n-((3n+9)+3)-4=0
We calculate terms in parentheses: -((3n+9)+3), so:
(3n+9)+3
We get rid of parentheses
3n+9+3
We add all the numbers together, and all the variables
3n+12
Back to the equation:
-(3n+12)
We get rid of parentheses
12n-3n-12-4=0
We add all the numbers together, and all the variables
9n-16=0
We move all terms containing n to the left, all other terms to the right
9n=16
n=16/9
n=1+7/9

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