4(3n-1)=2(4n+12)

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Solution for 4(3n-1)=2(4n+12) equation: 



4(3n-1)=2(4n+12)

We move all terms to the left:

4(3n-1)-(2(4n+12))=0

We multiply parentheses

12n-(2(4n+12))-4=0



We calculate terms in parentheses: -(2(4n+12)), so:

2(4n+12)

We multiply parentheses

8n+24

Back to the equation:

-(8n+24)



We get rid of parentheses

12n-8n-24-4=0

We add all the numbers together, and all the variables

4n-28=0

We move all terms containing n to the left, all other terms to the right

4n=28

n=28/4

n=7

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