4(3n-2)-5(5n+2)=2n-93

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Solution for 4(3n-2)-5(5n+2)=2n-93 equation: 



4(3n-2)-5(5n+2)=2n-93

We move all terms to the left:

4(3n-2)-5(5n+2)-(2n-93)=0

We multiply parentheses

12n-25n-(2n-93)-8-10=0

We get rid of parentheses

12n-25n-2n+93-8-10=0

We add all the numbers together, and all the variables

-15n+75=0

We move all terms containing n to the left, all other terms to the right

-15n=-75

n=-75/-15

n=+5

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