4(3n-5)=12n-20

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Solution for 4(3n-5)=12n-20 equation: 



4(3n-5)=12n-20

We move all terms to the left:

4(3n-5)-(12n-20)=0

We multiply parentheses

12n-(12n-20)-20=0

We get rid of parentheses

12n-12n+20-20=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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