4(3n-6)=3(n+2)+6

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Solution for 4(3n-6)=3(n+2)+6 equation: 



4(3n-6)=3(n+2)+6

We move all terms to the left:

4(3n-6)-(3(n+2)+6)=0

We multiply parentheses

12n-(3(n+2)+6)-24=0



We calculate terms in parentheses: -(3(n+2)+6), so:

3(n+2)+6

We multiply parentheses

3n+6+6

We add all the numbers together, and all the variables

3n+12

Back to the equation:

-(3n+12)



We get rid of parentheses

12n-3n-12-24=0

We add all the numbers together, and all the variables

9n-36=0

We move all terms containing n to the left, all other terms to the right

9n=36

n=36/9

n=4

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