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4(3p+1)=2(p-3)
We move all terms to the left:
4(3p+1)-(2(p-3))=0
We multiply parentheses
12p-(2(p-3))+4=0
We calculate terms in parentheses: -(2(p-3)), so:We get rid of parentheses
2(p-3)
We multiply parentheses
2p-6
Back to the equation:
-(2p-6)
12p-2p+6+4=0
We add all the numbers together, and all the variables
10p+10=0
We move all terms containing p to the left, all other terms to the right
10p=-10
p=-10/10
p=-1
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