4(3p+2)-5(6p-1)=2(p-8)-6(7p-4+4p)

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Solution for 4(3p+2)-5(6p-1)=2(p-8)-6(7p-4+4p) equation: 



4(3p+2)-5(6p-1)=2(p-8)-6(7p-4+4p)

We move all terms to the left:

4(3p+2)-5(6p-1)-(2(p-8)-6(7p-4+4p))=0

We add all the numbers together, and all the variables

4(3p+2)-5(6p-1)-(2(p-8)-6(11p-4))=0

We multiply parentheses

12p-30p-(2(p-8)-6(11p-4))+8+5=0



We calculate terms in parentheses: -(2(p-8)-6(11p-4)), so:

2(p-8)-6(11p-4)

We multiply parentheses

2p-66p-16+24

We add all the numbers together, and all the variables

-64p+8

Back to the equation:

-(-64p+8)



We add all the numbers together, and all the variables

-18p-(-64p+8)+13=0

We get rid of parentheses

-18p+64p-8+13=0

We add all the numbers together, and all the variables

46p+5=0

We move all terms containing p to the left, all other terms to the right

46p=-5

p=-5/46

p=-5/46

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