4(3q+10)=6(q-9)

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Solution for 4(3q+10)=6(q-9) equation: 



4(3q+10)=6(q-9)

We move all terms to the left:

4(3q+10)-(6(q-9))=0

We multiply parentheses

12q-(6(q-9))+40=0



We calculate terms in parentheses: -(6(q-9)), so:

6(q-9)

We multiply parentheses

6q-54

Back to the equation:

-(6q-54)



We get rid of parentheses

12q-6q+54+40=0

We add all the numbers together, and all the variables

6q+94=0

We move all terms containing q to the left, all other terms to the right

6q=-94

q=-94/6

q=-15+2/3

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