4(3q-2)=12q-8

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Solution for 4(3q-2)=12q-8 equation:


Simplifying
4(3q + -2) = 12q + -8

Reorder the terms:
4(-2 + 3q) = 12q + -8
(-2 * 4 + 3q * 4) = 12q + -8
(-8 + 12q) = 12q + -8

Reorder the terms:
-8 + 12q = -8 + 12q

Add '8' to each side of the equation.
-8 + 8 + 12q = -8 + 8 + 12q

Combine like terms: -8 + 8 = 0
0 + 12q = -8 + 8 + 12q
12q = -8 + 8 + 12q

Combine like terms: -8 + 8 = 0
12q = 0 + 12q
12q = 12q

Add '-12q' to each side of the equation.
12q + -12q = 12q + -12q

Combine like terms: 12q + -12q = 0
0 = 12q + -12q

Combine like terms: 12q + -12q = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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