4(3r+1)+2=6(1+2r)

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Solution for 4(3r+1)+2=6(1+2r) equation: 



4(3r+1)+2=6(1+2r)

We move all terms to the left:

4(3r+1)+2-(6(1+2r))=0

We add all the numbers together, and all the variables

4(3r+1)-(6(2r+1))+2=0

We multiply parentheses

12r-(6(2r+1))+4+2=0



We calculate terms in parentheses: -(6(2r+1)), so:

6(2r+1)

We multiply parentheses

12r+6

Back to the equation:

-(12r+6)



We add all the numbers together, and all the variables

12r-(12r+6)+6=0

We get rid of parentheses

12r-12r-6+6=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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