4(3r+1)=100

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Solution for 4(3r+1)=100 equation: 



4(3r+1)=100

We move all terms to the left:

4(3r+1)-(100)=0

We multiply parentheses

12r+4-100=0

We add all the numbers together, and all the variables

12r-96=0

We move all terms containing r to the left, all other terms to the right

12r=96

r=96/12

r=8

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