4(3r+1)=40+3r

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Solution for 4(3r+1)=40+3r equation: 



4(3r+1)=40+3r

We move all terms to the left:

4(3r+1)-(40+3r)=0

We add all the numbers together, and all the variables

4(3r+1)-(3r+40)=0

We multiply parentheses

12r-(3r+40)+4=0

We get rid of parentheses

12r-3r-40+4=0

We add all the numbers together, and all the variables

9r-36=0

We move all terms containing r to the left, all other terms to the right

9r=36

r=36/9

r=4

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