4(3r+4)=-(2r+5)

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Solution for 4(3r+4)=-(2r+5) equation: 



4(3r+4)=-(2r+5)

We move all terms to the left:

4(3r+4)-(-(2r+5))=0

We multiply parentheses

12r-(-(2r+5))+16=0



We calculate terms in parentheses: -(-(2r+5)), so:

-(2r+5)

We get rid of parentheses

-2r-5

Back to the equation:

-(-2r-5)



We get rid of parentheses

12r+2r+5+16=0

We add all the numbers together, and all the variables

14r+21=0

We move all terms containing r to the left, all other terms to the right

14r=-21

r=-21/14

r=-1+1/2

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