4(3r+4)=-8(2r+)

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Solution for 4(3r+4)=-8(2r+) equation: 



4(3r+4)=-8(2r+)

We move all terms to the left:

4(3r+4)-(-8(2r+))=0

We add all the numbers together, and all the variables

4(3r+4)-(-8(+2r))=0

We multiply parentheses

12r-(-8(+2r))+16=0



We calculate terms in parentheses: -(-8(+2r)), so:

-8(+2r)

We multiply parentheses

-16r

Back to the equation:

-(-16r)



We get rid of parentheses

12r+16r+16=0

We add all the numbers together, and all the variables

28r+16=0

We move all terms containing r to the left, all other terms to the right

28r=-16

r=-16/28

r=-4/7

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