4(3r+4)=16r-40

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Solution for 4(3r+4)=16r-40 equation: 



4(3r+4)=16r-40

We move all terms to the left:

4(3r+4)-(16r-40)=0

We multiply parentheses

12r-(16r-40)+16=0

We get rid of parentheses

12r-16r+40+16=0

We add all the numbers together, and all the variables

-4r+56=0

We move all terms containing r to the left, all other terms to the right

-4r=-56

r=-56/-4

r=+14

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