4(3r+5)=-8(2r+1)

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Solution for 4(3r+5)=-8(2r+1) equation: 



4(3r+5)=-8(2r+1)

We move all terms to the left:

4(3r+5)-(-8(2r+1))=0

We multiply parentheses

12r-(-8(2r+1))+20=0



We calculate terms in parentheses: -(-8(2r+1)), so:

-8(2r+1)

We multiply parentheses

-16r-8

Back to the equation:

-(-16r-8)



We get rid of parentheses

12r+16r+8+20=0

We add all the numbers together, and all the variables

28r+28=0

We move all terms containing r to the left, all other terms to the right

28r=-28

r=-28/28

r=-1

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