4(3r-4)=(r+9)+2

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Solution for 4(3r-4)=(r+9)+2 equation: 



4(3r-4)=(r+9)+2

We move all terms to the left:

4(3r-4)-((r+9)+2)=0

We multiply parentheses

12r-((r+9)+2)-16=0



We calculate terms in parentheses: -((r+9)+2), so:

(r+9)+2

We get rid of parentheses

r+9+2

We add all the numbers together, and all the variables

r+11

Back to the equation:

-(r+11)



We get rid of parentheses

12r-r-11-16=0

We add all the numbers together, and all the variables

11r-27=0

We move all terms containing r to the left, all other terms to the right

11r=27

r=27/11

r=2+5/11

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