4(3s+2)=2(b-3)

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Solution for 4(3s+2)=2(b-3) equation:


Simplifying
4(3s + 2) = 2(b + -3)

Reorder the terms:
4(2 + 3s) = 2(b + -3)
(2 * 4 + 3s * 4) = 2(b + -3)
(8 + 12s) = 2(b + -3)

Reorder the terms:
8 + 12s = 2(-3 + b)
8 + 12s = (-3 * 2 + b * 2)
8 + 12s = (-6 + 2b)

Solving
8 + 12s = -6 + 2b

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 12s = -6 + -8 + 2b

Combine like terms: 8 + -8 = 0
0 + 12s = -6 + -8 + 2b
12s = -6 + -8 + 2b

Combine like terms: -6 + -8 = -14
12s = -14 + 2b

Divide each side by '12'.
s = -1.166666667 + 0.1666666667b

Simplifying
s = -1.166666667 + 0.1666666667b

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