4(3t+4)=2(11t+11)

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Solution for 4(3t+4)=2(11t+11) equation: 



4(3t+4)=2(11t+11)

We move all terms to the left:

4(3t+4)-(2(11t+11))=0

We multiply parentheses

12t-(2(11t+11))+16=0



We calculate terms in parentheses: -(2(11t+11)), so:

2(11t+11)

We multiply parentheses

22t+22

Back to the equation:

-(22t+22)



We get rid of parentheses

12t-22t-22+16=0

We add all the numbers together, and all the variables

-10t-6=0

We move all terms containing t to the left, all other terms to the right

-10t=6

t=6/-10

t=-3/5

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