4(3t-2)-(5t+1)=-21-(3t-2)

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Solution for 4(3t-2)-(5t+1)=-21-(3t-2) equation: 



4(3t-2)-(5t+1)=-21-(3t-2)

We move all terms to the left:

4(3t-2)-(5t+1)-(-21-(3t-2))=0

We multiply parentheses

12t-(5t+1)-(-21-(3t-2))-8=0

We get rid of parentheses

12t-5t-(-21-(3t-2))-1-8=0



We calculate terms in parentheses: -(-21-(3t-2)), so:

-21-(3t-2)

determiningTheFunctionDomain
-(3t-2)-21

We get rid of parentheses

-3t+2-21

We add all the numbers together, and all the variables

-3t-19

Back to the equation:

-(-3t-19)



We add all the numbers together, and all the variables

7t-(-3t-19)-9=0

We get rid of parentheses

7t+3t+19-9=0

We add all the numbers together, and all the variables

10t+10=0

We move all terms containing t to the left, all other terms to the right

10t=-10

t=-10/10

t=-1

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