4(3t-b)=12t-20

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Solution for 4(3t-b)=12t-20 equation:


Simplifying
4(3t + -1b) = 12t + -20

Reorder the terms:
4(-1b + 3t) = 12t + -20
(-1b * 4 + 3t * 4) = 12t + -20
(-4b + 12t) = 12t + -20

Reorder the terms:
-4b + 12t = -20 + 12t

Add '-12t' to each side of the equation.
-4b + 12t + -12t = -20 + 12t + -12t

Combine like terms: 12t + -12t = 0
-4b + 0 = -20 + 12t + -12t
-4b = -20 + 12t + -12t

Combine like terms: 12t + -12t = 0
-4b = -20 + 0
-4b = -20

Solving
-4b = -20

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '-4'.
b = 5

Simplifying
b = 5

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