4(3u+1)+5u+5=6(u+3)+2u

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Solution for 4(3u+1)+5u+5=6(u+3)+2u equation: 



4(3u+1)+5u+5=6(u+3)+2u

We move all terms to the left:

4(3u+1)+5u+5-(6(u+3)+2u)=0

We add all the numbers together, and all the variables

5u+4(3u+1)-(6(u+3)+2u)+5=0

We multiply parentheses

5u+12u-(6(u+3)+2u)+4+5=0



We calculate terms in parentheses: -(6(u+3)+2u), so:

6(u+3)+2u

We add all the numbers together, and all the variables

2u+6(u+3)

We multiply parentheses

2u+6u+18

We add all the numbers together, and all the variables

8u+18

Back to the equation:

-(8u+18)



We add all the numbers together, and all the variables

17u-(8u+18)+9=0

We get rid of parentheses

17u-8u-18+9=0

We add all the numbers together, and all the variables

9u-9=0

We move all terms containing u to the left, all other terms to the right

9u=9

u=9/9

u=1

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