4(3u-3)+4u+4=4(u+5)-2u

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Solution for 4(3u-3)+4u+4=4(u+5)-2u equation: 



4(3u-3)+4u+4=4(u+5)-2u

We move all terms to the left:

4(3u-3)+4u+4-(4(u+5)-2u)=0

We add all the numbers together, and all the variables

4u+4(3u-3)-(4(u+5)-2u)+4=0

We multiply parentheses

4u+12u-(4(u+5)-2u)-12+4=0



We calculate terms in parentheses: -(4(u+5)-2u), so:

4(u+5)-2u

We add all the numbers together, and all the variables

-2u+4(u+5)

We multiply parentheses

-2u+4u+20

We add all the numbers together, and all the variables

2u+20

Back to the equation:

-(2u+20)



We add all the numbers together, and all the variables

16u-(2u+20)-8=0

We get rid of parentheses

16u-2u-20-8=0

We add all the numbers together, and all the variables

14u-28=0

We move all terms containing u to the left, all other terms to the right

14u=28

u=28/14

u=2

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