4(3v-5)=28

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Solution for 4(3v-5)=28 equation: 



4(3v-5)=28

We move all terms to the left:

4(3v-5)-(28)=0

We multiply parentheses

12v-20-28=0

We add all the numbers together, and all the variables

12v-48=0

We move all terms containing v to the left, all other terms to the right

12v=48

v=48/12

v=4

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