4(3w+2)-5(6w-1)=2(w-8)-6(7w-4)+4w-4

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Solution for 4(3w+2)-5(6w-1)=2(w-8)-6(7w-4)+4w-4 equation: 



4(3w+2)-5(6w-1)=2(w-8)-6(7w-4)+4w-4

We move all terms to the left:

4(3w+2)-5(6w-1)-(2(w-8)-6(7w-4)+4w-4)=0

We multiply parentheses

12w-30w-(2(w-8)-6(7w-4)+4w-4)+8+5=0



We calculate terms in parentheses: -(2(w-8)-6(7w-4)+4w-4), so:

2(w-8)-6(7w-4)+4w-4

We add all the numbers together, and all the variables

4w+2(w-8)-6(7w-4)-4

We multiply parentheses

4w+2w-42w-16+24-4

We add all the numbers together, and all the variables

-36w+4

Back to the equation:

-(-36w+4)



We add all the numbers together, and all the variables

-18w-(-36w+4)+13=0

We get rid of parentheses

-18w+36w-4+13=0

We add all the numbers together, and all the variables

18w+9=0

We move all terms containing w to the left, all other terms to the right

18w=-9

w=-9/18

w=-1/2

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