4(3x+1)+4(x-3)=

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Solution for 4(3x+1)+4(x-3)= equation:


Simplifying
4(3x + 1) + 4(x + -3) = 0

Reorder the terms:
4(1 + 3x) + 4(x + -3) = 0
(1 * 4 + 3x * 4) + 4(x + -3) = 0
(4 + 12x) + 4(x + -3) = 0

Reorder the terms:
4 + 12x + 4(-3 + x) = 0
4 + 12x + (-3 * 4 + x * 4) = 0
4 + 12x + (-12 + 4x) = 0

Reorder the terms:
4 + -12 + 12x + 4x = 0

Combine like terms: 4 + -12 = -8
-8 + 12x + 4x = 0

Combine like terms: 12x + 4x = 16x
-8 + 16x = 0

Solving
-8 + 16x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 16x = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 16x = 0 + 8
16x = 0 + 8

Combine like terms: 0 + 8 = 8
16x = 8

Divide each side by '16'.
x = 0.5

Simplifying
x = 0.5

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