4(3x+1)-(2x-5)+16=2(3x+1)+(2x+5)

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Solution for 4(3x+1)-(2x-5)+16=2(3x+1)+(2x+5) equation: 



4(3x+1)-(2x-5)+16=2(3x+1)+(2x+5)

We move all terms to the left:

4(3x+1)-(2x-5)+16-(2(3x+1)+(2x+5))=0

We multiply parentheses

12x-(2x-5)-(2(3x+1)+(2x+5))+4+16=0

We get rid of parentheses

12x-2x-(2(3x+1)+(2x+5))+5+4+16=0



We calculate terms in parentheses: -(2(3x+1)+(2x+5)), so:

2(3x+1)+(2x+5)

We multiply parentheses

6x+(2x+5)+2

We get rid of parentheses

6x+2x+5+2

We add all the numbers together, and all the variables

8x+7

Back to the equation:

-(8x+7)



We add all the numbers together, and all the variables

10x-(8x+7)+25=0

We get rid of parentheses

10x-8x-7+25=0

We add all the numbers together, and all the variables

2x+18=0

We move all terms containing x to the left, all other terms to the right

2x=-18

x=-18/2

x=-9

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