4(3x+1)-2(1x-2)=13

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Solution for 4(3x+1)-2(1x-2)=13 equation:


Simplifying
4(3x + 1) + -2(1x + -2) = 13

Reorder the terms:
4(1 + 3x) + -2(1x + -2) = 13
(1 * 4 + 3x * 4) + -2(1x + -2) = 13
(4 + 12x) + -2(1x + -2) = 13

Reorder the terms:
4 + 12x + -2(-2 + 1x) = 13
4 + 12x + (-2 * -2 + 1x * -2) = 13
4 + 12x + (4 + -2x) = 13

Reorder the terms:
4 + 4 + 12x + -2x = 13

Combine like terms: 4 + 4 = 8
8 + 12x + -2x = 13

Combine like terms: 12x + -2x = 10x
8 + 10x = 13

Solving
8 + 10x = 13

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 10x = 13 + -8

Combine like terms: 8 + -8 = 0
0 + 10x = 13 + -8
10x = 13 + -8

Combine like terms: 13 + -8 = 5
10x = 5

Divide each side by '10'.
x = 0.5

Simplifying
x = 0.5

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