4(3x+1)-2(3x-2)=15

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Solution for 4(3x+1)-2(3x-2)=15 equation: 



4(3x+1)-2(3x-2)=15

We move all terms to the left:

4(3x+1)-2(3x-2)-(15)=0

We multiply parentheses

12x-6x+4+4-15=0

We add all the numbers together, and all the variables

6x-7=0

We move all terms containing x to the left, all other terms to the right

6x=7

x=7/6

x=1+1/6

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