4(3x+1)-4x=8-2(x-3)

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Solution for 4(3x+1)-4x=8-2(x-3) equation: 



4(3x+1)-4x=8-2(x-3)

We move all terms to the left:

4(3x+1)-4x-(8-2(x-3))=0

We add all the numbers together, and all the variables

-4x+4(3x+1)-(8-2(x-3))=0

We multiply parentheses

-4x+12x-(8-2(x-3))+4=0



We calculate terms in parentheses: -(8-2(x-3)), so:

8-2(x-3)

determiningTheFunctionDomain
-2(x-3)+8

We multiply parentheses

-2x+6+8

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We add all the numbers together, and all the variables

8x-(-2x+14)+4=0

We get rid of parentheses

8x+2x-14+4=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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