4(3x+1)-8=12x-4

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Solution for 4(3x+1)-8=12x-4 equation:


Simplifying
4(3x + 1) + -8 = 12x + -4

Reorder the terms:
4(1 + 3x) + -8 = 12x + -4
(1 * 4 + 3x * 4) + -8 = 12x + -4
(4 + 12x) + -8 = 12x + -4

Reorder the terms:
4 + -8 + 12x = 12x + -4

Combine like terms: 4 + -8 = -4
-4 + 12x = 12x + -4

Reorder the terms:
-4 + 12x = -4 + 12x

Add '4' to each side of the equation.
-4 + 4 + 12x = -4 + 4 + 12x

Combine like terms: -4 + 4 = 0
0 + 12x = -4 + 4 + 12x
12x = -4 + 4 + 12x

Combine like terms: -4 + 4 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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