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4(3x+1)=-3(2x-5)+4x
We move all terms to the left:
4(3x+1)-(-3(2x-5)+4x)=0
We multiply parentheses
12x-(-3(2x-5)+4x)+4=0
We calculate terms in parentheses: -(-3(2x-5)+4x), so:We get rid of parentheses
-3(2x-5)+4x
We add all the numbers together, and all the variables
4x-3(2x-5)
We multiply parentheses
4x-6x+15
We add all the numbers together, and all the variables
-2x+15
Back to the equation:
-(-2x+15)
12x+2x-15+4=0
We add all the numbers together, and all the variables
14x-11=0
We move all terms containing x to the left, all other terms to the right
14x=11
x=11/14
x=11/14
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