4(3x+1)=-3(2x-5)+4x

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Solution for 4(3x+1)=-3(2x-5)+4x equation: 



4(3x+1)=-3(2x-5)+4x

We move all terms to the left:

4(3x+1)-(-3(2x-5)+4x)=0

We multiply parentheses

12x-(-3(2x-5)+4x)+4=0



We calculate terms in parentheses: -(-3(2x-5)+4x), so:

-3(2x-5)+4x

We add all the numbers together, and all the variables

4x-3(2x-5)

We multiply parentheses

4x-6x+15

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We get rid of parentheses

12x+2x-15+4=0

We add all the numbers together, and all the variables

14x-11=0

We move all terms containing x to the left, all other terms to the right

14x=11

x=11/14

x=11/14

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