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4(3x+1)=-3(4x-4)+5x
We move all terms to the left:
4(3x+1)-(-3(4x-4)+5x)=0
We multiply parentheses
12x-(-3(4x-4)+5x)+4=0
We calculate terms in parentheses: -(-3(4x-4)+5x), so:We get rid of parentheses
-3(4x-4)+5x
We add all the numbers together, and all the variables
5x-3(4x-4)
We multiply parentheses
5x-12x+12
We add all the numbers together, and all the variables
-7x+12
Back to the equation:
-(-7x+12)
12x+7x-12+4=0
We add all the numbers together, and all the variables
19x-8=0
We move all terms containing x to the left, all other terms to the right
19x=8
x=8/19
x=8/19
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