4(3x+1)=-4(2x-4)-3x

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Solution for 4(3x+1)=-4(2x-4)-3x equation: 



4(3x+1)=-4(2x-4)-3x

We move all terms to the left:

4(3x+1)-(-4(2x-4)-3x)=0

We multiply parentheses

12x-(-4(2x-4)-3x)+4=0



We calculate terms in parentheses: -(-4(2x-4)-3x), so:

-4(2x-4)-3x

We add all the numbers together, and all the variables

-3x-4(2x-4)

We multiply parentheses

-3x-8x+16

We add all the numbers together, and all the variables

-11x+16

Back to the equation:

-(-11x+16)



We get rid of parentheses

12x+11x-16+4=0

We add all the numbers together, and all the variables

23x-12=0

We move all terms containing x to the left, all other terms to the right

23x=12

x=12/23

x=12/23

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