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4(3x+1)=2(6x+5)
We move all terms to the left:
4(3x+1)-(2(6x+5))=0
We multiply parentheses
12x-(2(6x+5))+4=0
We calculate terms in parentheses: -(2(6x+5)), so:We get rid of parentheses
2(6x+5)
We multiply parentheses
12x+10
Back to the equation:
-(12x+10)
12x-12x-10+4=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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