4(3x+1)=2(6x-5)+14

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Solution for 4(3x+1)=2(6x-5)+14 equation:


Simplifying
4(3x + 1) = 2(6x + -5) + 14

Reorder the terms:
4(1 + 3x) = 2(6x + -5) + 14
(1 * 4 + 3x * 4) = 2(6x + -5) + 14
(4 + 12x) = 2(6x + -5) + 14

Reorder the terms:
4 + 12x = 2(-5 + 6x) + 14
4 + 12x = (-5 * 2 + 6x * 2) + 14
4 + 12x = (-10 + 12x) + 14

Reorder the terms:
4 + 12x = -10 + 14 + 12x

Combine like terms: -10 + 14 = 4
4 + 12x = 4 + 12x

Add '-4' to each side of the equation.
4 + -4 + 12x = 4 + -4 + 12x

Combine like terms: 4 + -4 = 0
0 + 12x = 4 + -4 + 12x
12x = 4 + -4 + 12x

Combine like terms: 4 + -4 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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