4(3x+1)=25+3(2x+-1)

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Solution for 4(3x+1)=25+3(2x+-1) equation:



4(3x+1)=25+3(2x+-1)
We move all terms to the left:
4(3x+1)-(25+3(2x+-1))=0
We add all the numbers together, and all the variables
4(3x+1)-(25+3(2x-1))=0
We multiply parentheses
12x-(25+3(2x-1))+4=0
We calculate terms in parentheses: -(25+3(2x-1)), so:
25+3(2x-1)
determiningTheFunctionDomain 3(2x-1)+25
We multiply parentheses
6x-3+25
We add all the numbers together, and all the variables
6x+22
Back to the equation:
-(6x+22)
We get rid of parentheses
12x-6x-22+4=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3

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