4(3x+1)=40+x

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Solution for 4(3x+1)=40+x equation: 



4(3x+1)=40+x

We move all terms to the left:

4(3x+1)-(40+x)=0

We add all the numbers together, and all the variables

4(3x+1)-(x+40)=0

We multiply parentheses

12x-(x+40)+4=0

We get rid of parentheses

12x-x-40+4=0

We add all the numbers together, and all the variables

11x-36=0

We move all terms containing x to the left, all other terms to the right

11x=36

x=36/11

x=3+3/11

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