4(3x+1)=7(x+4)-2(x-4)

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Solution for 4(3x+1)=7(x+4)-2(x-4) equation: 



4(3x+1)=7(x+4)-2(x-4)

We move all terms to the left:

4(3x+1)-(7(x+4)-2(x-4))=0

We multiply parentheses

12x-(7(x+4)-2(x-4))+4=0



We calculate terms in parentheses: -(7(x+4)-2(x-4)), so:

7(x+4)-2(x-4)

We multiply parentheses

7x-2x+28+8

We add all the numbers together, and all the variables

5x+36

Back to the equation:

-(5x+36)



We get rid of parentheses

12x-5x-36+4=0

We add all the numbers together, and all the variables

7x-32=0

We move all terms containing x to the left, all other terms to the right

7x=32

x=32/7

x=4+4/7

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