4(3x+1)=78

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Solution for 4(3x+1)=78 equation: 



4(3x+1)=78

We move all terms to the left:

4(3x+1)-(78)=0

We multiply parentheses

12x+4-78=0

We add all the numbers together, and all the variables

12x-74=0

We move all terms containing x to the left, all other terms to the right

12x=74

x=74/12

x=6+1/6

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