4(3x+11)=(16+4x)

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Solution for 4(3x+11)=(16+4x) equation: 



4(3x+11)=(16+4x)

We move all terms to the left:

4(3x+11)-((16+4x))=0

We add all the numbers together, and all the variables

4(3x+11)-((4x+16))=0

We multiply parentheses

12x-((4x+16))+44=0



We calculate terms in parentheses: -((4x+16)), so:

(4x+16)

We get rid of parentheses

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

12x-4x-16+44=0

We add all the numbers together, and all the variables

8x+28=0

We move all terms containing x to the left, all other terms to the right

8x=-28

x=-28/8

x=-3+1/2

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