4(3x+1x)+7-5x=8(-5)(5x-6x)+23

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Solution for 4(3x+1x)+7-5x=8(-5)(5x-6x)+23 equation: 



4(3x+1x)+7-5x=8(-5)(5x-6x)+23

We move all terms to the left:

4(3x+1x)+7-5x-(8(-5)(5x-6x)+23)=0

We add all the numbers together, and all the variables

4(+4x)-5x-(8(-5)(-1x)+23)+7=0

We add all the numbers together, and all the variables

-5x+4(+4x)-(8(-5)(-1x)+23)+7=0

We multiply parentheses

-5x+16x-(8(-5)(-1x)+23)+7=0

We multiply parentheses ..

-5x+16x-(8(+5x)+23)+7=0



We calculate terms in parentheses: -(8(+5x)+23), so:

8(+5x)+23

We multiply parentheses

40x+23

Back to the equation:

-(40x+23)



We add all the numbers together, and all the variables

11x-(40x+23)+7=0

We get rid of parentheses

11x-40x-23+7=0

We add all the numbers together, and all the variables

-29x-16=0

We move all terms containing x to the left, all other terms to the right

-29x=16

x=16/-29

x=-16/29

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