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4(3x+2)+2(5x-6)=5(2x+4)+
We move all terms to the left:
4(3x+2)+2(5x-6)-(5(2x+4)+)=0
We multiply parentheses
12x+10x-(5(2x+4)+)+8-12=0
We calculate terms in parentheses: -(5(2x+4)+), so:We add all the numbers together, and all the variables
5(2x+4)+
We add all the numbers together, and all the variables
5(2x+4)
We multiply parentheses
10x+20
Back to the equation:
-(10x+20)
22x-(10x+20)-4=0
We get rid of parentheses
22x-10x-20-4=0
We add all the numbers together, and all the variables
12x-24=0
We move all terms containing x to the left, all other terms to the right
12x=24
x=24/12
x=2
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