4(3x+2)+27=17x+6-5x+29

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Solution for 4(3x+2)+27=17x+6-5x+29 equation: 



4(3x+2)+27=17x+6-5x+29

We move all terms to the left:

4(3x+2)+27-(17x+6-5x+29)=0

We add all the numbers together, and all the variables

4(3x+2)-(12x+35)+27=0

We multiply parentheses

12x-(12x+35)+8+27=0

We get rid of parentheses

12x-12x-35+8+27=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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