4(3x+2)-11+x=3(3x-2)+x

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Solution for 4(3x+2)-11+x=3(3x-2)+x equation: 



4(3x+2)-11+x=3(3x-2)+x

We move all terms to the left:

4(3x+2)-11+x-(3(3x-2)+x)=0

We add all the numbers together, and all the variables

x+4(3x+2)-(3(3x-2)+x)-11=0

We multiply parentheses

x+12x-(3(3x-2)+x)+8-11=0



We calculate terms in parentheses: -(3(3x-2)+x), so:

3(3x-2)+x

We add all the numbers together, and all the variables

x+3(3x-2)

We multiply parentheses

x+9x-6

We add all the numbers together, and all the variables

10x-6

Back to the equation:

-(10x-6)



We add all the numbers together, and all the variables

13x-(10x-6)-3=0

We get rid of parentheses

13x-10x+6-3=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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