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4(3x+2)-1=3(2x+3)+6x-2
We move all terms to the left:
4(3x+2)-1-(3(2x+3)+6x-2)=0
We multiply parentheses
12x-(3(2x+3)+6x-2)+8-1=0
We calculate terms in parentheses: -(3(2x+3)+6x-2), so:We add all the numbers together, and all the variables
3(2x+3)+6x-2
We add all the numbers together, and all the variables
6x+3(2x+3)-2
We multiply parentheses
6x+6x+9-2
We add all the numbers together, and all the variables
12x+7
Back to the equation:
-(12x+7)
12x-(12x+7)+7=0
We get rid of parentheses
12x-12x-7+7=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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