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4(3x+2)-3x=9(x+2)-10
We move all terms to the left:
4(3x+2)-3x-(9(x+2)-10)=0
We add all the numbers together, and all the variables
-3x+4(3x+2)-(9(x+2)-10)=0
We multiply parentheses
-3x+12x-(9(x+2)-10)+8=0
We calculate terms in parentheses: -(9(x+2)-10), so:We add all the numbers together, and all the variables
9(x+2)-10
We multiply parentheses
9x+18-10
We add all the numbers together, and all the variables
9x+8
Back to the equation:
-(9x+8)
9x-(9x+8)+8=0
We get rid of parentheses
9x-9x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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